 Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        if x+y+z = 0 then x2y2+y2z2+x2z2/ x4+y4+z4 = ,Answer given was ½ but how it came tell please  `
3 years ago Ashutosh Mohan Sharma
180 Points
```							(x-y)2>=0; Therefore, x2+y2>=2xt>=0Also using Nima J's proof, it follows that(X2-y2)2>=0; Therefore, x4+y4>=2x2y2Dividing both sides by 2 gives(a) ½(x2+y2)>=xy and(b) ½(x4+y4)>=x2y2Now since (x2+y2)>=2xy; it follows that(x2+y2)(z2+w2)>=(2xy)(2zw)=4xyzwTherefore, multiplying the factors gives:(c) x2z2+x2w2+y2z2+y2w2>=4xyzwNowX4+y4+z4+w4 =½[(x4+z4)+ (x4+w4)+ (y4+z4)+ (y4+w4)]>=[(x2z2)+ (x2w2)+ (y2z2)+ (y2w2)]>= 4xyzw; equations (b) &(c)Therefore,X4+y4+z4+w4>=4xyzw
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on 9 grade maths

View all Questions »  ### Course Features

• 728 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions