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If x= under root a+2b + under root a-2b/ under root a+2b - under root a-2b prove thatb^2x^2-abx+b^2=0

nayakaniwow@gmail.com , 6 Years ago
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ADARSH SINGH

Last Activity: 6 Years ago

x =\sqrt{ a+2b }+\sqrt{ a-2b} / (\sqrt{a+2b }-\sqrt{ a-2b})
 
rationalising the given equation, we will get ,(note; to rationalise, divide and multiply whole equation by it’s rationalising factor.)
 
x = a+\sqrt{ a^{}2-4b^{}2}/2b
 
substitute this value in given equation , and you will get following :-
 
b2x2-abx+b2   =   < a+\sqrt{a^{}2-4b^{}2}/4b> - < a^{}2 + )}a \sqrt{a^{}2- 4b^{}2}/2> + b^{}2
 
which ,  ultimately becomes zero. hence, proved.
 
 
 

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