Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        If a+b+c=0, find the value of1/2a2+bc+1/2b2+ca+1/2c2+ab`
6 months ago Saurabh Koranglekar
7878 Points
```							Dear studentTake out 1/2 common from required expression0.5( a+b+c)^2= 0.5*0*0 =0Regards
```
6 months ago
```							Dear student a + b + c = 0∴ a = -(b + c), b = -(c + a) , c = -(a + b)Now, (2a² + bc ) = (a² + a² + bc)= {a² + a(-b - c) + bc}= a² - ab - ac + bc = a(a - b) -c(a - c) = (a - c)(a - b) ------------(1)similarly, (2b² + ca) = (b - c)(b - a) -------------(2)(2c² + ab) = (c - a)(c - b) --------------(3)now, LHS = 1/(2a² + bc ) + 1/(2b² + ca) + 1/(2c² + ab)= 1/(a - b)(a - c) + 1/(b - c)(b - a) + 1/(c - a)(c - b)= - 1/(a- b)(c - a) -1/(b - c)(a - b) - 1/(c - a)(b - c)= -[(b -c ) + (c - a) + (a - b)]/(a - b)(b - c)(c - a)]= 0 = RHSHope this helps Good Luck
```
6 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on 9 grade maths

View all Questions »  ### Course Features

• 728 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions