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`        if a^4+b^4=a^2b^2  show that a^6+b^6=0showshowshowshowshowshowshowshowshowshowshowshowshowshowshow`
one year ago

```							Given, a^(4) + b^(4) = a^(2)b^(2)To Prove = a^(6) + b^(6) = 0We can write a^(6)+b^(6) as (a^(2))^(3) + (b^(2))^(3)So, we got the formula of x^(3)+y^(3)where x= a^2 and y= b^(2)Now open the formula = x^3+y^3 = (x+y)(x^2+y^2-xy)Now, put the values of x and y,a^6+b^6 = (a^2+b^2)(a^4+b^4-a^2b^2)and given, a^4+b^4=a^2b^2So, a^6+b^6 = (a^2+b^2)(a^2b^2 - a^2b^2)therefore, a^6+b^6 = 0
```
one year ago
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