Given BE and CF are the altitudes of the ∆ABC.P,Q are on BE and extension of CF respectively, such that BP=AC,CQ=AB, prove that AP is perpendicular to AQ

Question

Prasanjeet Nayak · Answer

From AB perpendicular to CQ and BE perpendicular to AC

angleABE=angleQCA

SinceAB=CQ and BP =CA,

TriangleABP = TriangleQCA (S.A.S.)

angleBAP = angleCQA,

angleQAP = angleQAF + angleBAP = angleQAF + angleCQA

= 180 °- 90 = 90.

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Given BE and CF are the altitudes of the ∆ABC.P,Q are on BE and extension of CF respectively, such that BP=AC,CQ=AB, prove that AP is perpendicular to AQ

Given BE and CF are the altitudes of the ∆ABC.P,Q are on BE and extension of CF respectively, such that BP=AC,CQ=AB, prove that AP is perpendicular to AQ

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Given BE and CF are the altitudes of the ∆ABC.P,Q are on BE and extension of CF respectively, such that BP=AC,CQ=AB, prove that AP is perpendicular to AQ

Given BE and CF are the altitudes of the ∆ABC.P,Q are on BE and extension of CF respectively, such that BP=AC,CQ=AB, prove that AP is perpendicular to AQ

1 Answers

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