Pawan Prajapati
Last Activity: 4 Years ago
SoL Consider triangles BFC and CEB,
We have BE = CF [Given]
BC = CB [Common}
and LBFC = LBEC [90° each]
.. ABFC :: ACEB [lUlS rule]
==> LFBC = LECB
i.e., LABC = LACB
==> AC = AB
BC
[CPCT]
[Sides opposite t.o equal angles of a triangles are equal.]
==> A ABC is an isosceles triangle. •