Palak
Last Activity: 5 Years ago
Given: ABCD is a quadrilateral in which diagonal AC and BD intersect at O , and ar(AOB) = ar(DOC)
To prove : angle BDA = angle DBC
Proof : ar(AOB) =ar(DOC)
Adding ar(BOC) to both side
ar(ACB)=ar(DBC)
We know triangles having same base and equal areas lies between same paralles
Therefore, AD|| BC
Now angle BDA = DBC ( alternate interior angle )
Hence proved
