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A triangle and a parallelogram have the same base and the sam£ area. If the sides of the triangle are 26 cm, 28 cm and 30 cm, and the parallelogram stands on the base 28 cm, find the height of the parallelogram.

A triangle and a parallelogram have the same base and the sam£ area. If the sides of the triangle are 26 cm, 28 cm and 30 cm, and the parallelogram stands on the base 28 cm, find the height of the parallelogram.

Grade:12th pass

1 Answers

Pawan Prajapati
askIITians Faculty 60787 Points
3 years ago
Area of parallelogram = area of triangle. ...(i) Let h be the height in cm of the parallelogram. Sides of the triangle are 26 cm, 28 .cm and 30 cm. 26 + 28 + 30 s = 2 = 42. Now, area of the triangle = v'42<42 -26)(42 -28)(42 -30) cm2 = v'42x16 x14x12 cm2 = 336 cm2 Area of the parallelogram = base x height = 28 x h From (i), we have Substituting the values of areas from (ii) and ( iii ) in (i), we have 28 x h = 336 h = 12 cm. Hence, height of the parallelogram = 12 cm.

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