A triangle and a parallelogram have the same base and the sam£ area. If the sides of the triangle are 26 cm, 28 cm and 30 cm, and the parallelogram stands on the base 28 cm, find the height of the parallelogram.

Question

Pawan Prajapati · Answer

Area of parallelogram = area of triangle. ...(i) Let h be the height in cm of the parallelogram. Sides of the triangle are 26 cm, 28 .cm and 30 cm. 26 + 28 + 30 s = 2 = 42. Now, area of the triangle = v'42<42 -26)(42 -28)(42 -30) cm2 = v'42x16 x14x12 cm2 = 336 cm2 Area of the parallelogram = base x height = 28 x h From (i), we have Substituting the values of areas from (ii) and ( iii ) in (i), we have 28 x h = 336 h = 12 cm. Hence, height of the parallelogram = 12 cm.

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A triangle and a parallelogram have the same base and the sam£ area. If the sides of the triangle are 26 cm, 28 cm and 30 cm, and the parallelogram stands on the base 28 cm, find the height of the parallelogram.

A triangle and a parallelogram have the same base and the sam£ area. If the sides of the triangle are 26 cm, 28 cm and 30 cm, and the parallelogram stands on the base 28 cm, find the height of the parallelogram.

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