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A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the convex lens if the image is equal to the size of the object? Also find the power of the lens.
Dear StudentObject distance, u= – 50 cmImage distance, v= 50 cmFocal length = fAccording to the lens formula,u = -50 cm v = + 50 cm.f =? 1/f = 1/v – 1/u1/f = 1/50 + 1/50f = + 25 cm. = 0.25 mPower of lens (P) = 1/f = 1/ 0.25 = + 4D.Thanks
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