Pawan Prajapati
Last Activity: 3 Years ago
(i) Proof: Since E and F are
respectively the mid-points of AC
and AB of !!ABC. .
1 E
• EF ll BC and EF = 2 Bc
[Mid-point theorem] B 0 c
Also, BD = iBC [•: D is mid-point of BC]
• EF II BD and EF = BD.
=> BDEF is a parallelogram. [In a quadrilateral,
if a pair of Op(>Osite sides is equal and parallel, then it is a parallelogram.]
(ii) DF is diagonal. I
:. ar ar(DEF) = 4ar(ABC).
(iii) ar(BDEF) = ar(BDF) + ar(DEF). = 2.cu(DEF) [From (i)J
= 2 x °14
ar(ABC) = 21
(ABC).