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Using suitable algebraic identity, solve 1092 2 ejc jencjkewvhjkv j

Using suitable algebraic identity, solve 10922
 
ejc jencjkewvhjkv j

Grade:12

1 Answers

Harshit Singh
askIITians Faculty 5963 Points
9 months ago
Dear Student

Use the algebraic identity: (a + b)² = a² + 2ab + b²

Now, 1092 = 1000 + 92

So, 10922= (1000 + 92)2

(1000 + 92)2= ( 1000 )² + 2 × 1000 × 92 + ( 92 )²

= 1000000 + 184000 + 8464

Thus, 10922= 1192464.

Thanks

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