Grade 128 grade maths
Using a^2 – b^2 = (a + b) (a – b), find51^2– 49^2???????????????
Using a^2 – b^2 = (a + b) (a – b), find
51^2– 49^2???????????????
1 Answer
Harshit Singh
Dear Student
51^2 –49^2
= (51 + 49)(51 - 49)
= 100 x 2
= 200
Thanks
51^2 –49^2
= (51 + 49)(51 - 49)
= 100 x 2
= 200
Thanks
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