Grade 128 grade maths
Using a^2 – b^2 = (a + b) (a – b), find(1.02)^2– (0.98)^2
Using a^2 – b^2 = (a + b) (a – b), find
(1.02)^2– (0.98)^2
1 Answer
Harshit Singh
Dear Student
(1.02)^2– (0.98)^2
= (1.02 + 0.98)(1.02 - 0.98)
= 2 x 0.04
= 0.08
Thanks
(1.02)^2– (0.98)^2
= (1.02 + 0.98)(1.02 - 0.98)
= 2 x 0.04
= 0.08
Thanks
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