Askiitians Tutor Team
Last Activity: 9 Months ago
To determine the number of decimal places after the decimal expansion of the rational number \(\dfrac{11}{2^3 \cdot 5^2}\), we need to examine the prime factorization of the denominator and check if the decimal expansion will terminate.
1. **Prime factorization of the denominator:**
The denominator is \(2^3 \cdot 5^2\).
We have two prime factors: 2 and 5, both of which are the prime factors of 10.
2. **Condition for termination of the decimal expansion:**
A rational number has a terminating decimal expansion if and only if the denominator (when the fraction is in its simplest form) has no prime factors other than 2 and 5.
3. **Simplifying the expression:**
The denominator is \(2^3 \cdot 5^2\), which is already in the form of prime factors of 2 and 5.
4. **Number of decimal places:**
For the decimal expansion to terminate, we can convert the denominator into powers of 10 by multiplying the numerator and denominator by appropriate powers of 2 or 5. The number of decimal places corresponds to how many powers of 10 are in the denominator after simplification.
The denominator \(2^3 \cdot 5^2 = 8 \cdot 25 = 200\).
5. **Now calculate the decimal:**
\[
\dfrac{11}{200} = 0.055
\]
The decimal expansion is \(0.055\), which terminates after **three decimal places**.
Thus, the correct answer is:
**C) Three decimal places**.