Grade 128 grade maths
Subtract 4a – 7ab + 3b + 12 from 12a – 9ab + 5b – 3
Subtract 4a – 7ab + 3b + 12 from 12a – 9ab + 5b – 3
1 Answer
Harshit Singh
Dear Student
(12a - 9ab + 5b - 3) - (4a - 7ab + 3b + 12)
= 12a - 9ab + 5b - 3 - 4a + 7ab - 3b - 12
= 12a – 4a -9ab + 7ab +5b – 3b -3 -12
= 8a - 2ab + 2b - 15
Thanks
(12a - 9ab + 5b - 3) - (4a - 7ab + 3b + 12)
= 12a - 9ab + 5b - 3 - 4a + 7ab - 3b - 12
= 12a – 4a -9ab + 7ab +5b – 3b -3 -12
= 8a - 2ab + 2b - 15
Thanks
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