Grade 128 grade maths
Subtract: 3a (a + b + c ) – 2 b (a – b + c) from 4c ( – a + b + c )
Subtract: 3a (a + b + c ) – 2 b (a – b + c) from 4c ( – a + b + c )
1 Answer
Harshit Singh
Dear Student
4c (–a + b + c )- (3a (a + b + c )–2 b (a–b + c))
= (-4ac + 4bc + 4c^2) - (3a^2+ 3ab + 3ac–( 2ab–2b^2 + 2bc ))
= -4ac + 4bc + 4c^2- (3a^2+ 3ab + 3ac - 2ab + 2b^2 - 2bc)
= -4ac + 4bc + 4c^2- 3a^2- 3ab - 3ac +2ab–2b^2 + 2bc
= -7ac+6bc+4c2-3a2–ab–2b^2
Thanks
4c (–a + b + c )- (3a (a + b + c )–2 b (a–b + c))
= (-4ac + 4bc + 4c^2) - (3a^2+ 3ab + 3ac–( 2ab–2b^2 + 2bc ))
= -4ac + 4bc + 4c^2- (3a^2+ 3ab + 3ac - 2ab + 2b^2 - 2bc)
= -4ac + 4bc + 4c^2- 3a^2- 3ab - 3ac +2ab–2b^2 + 2bc
= -7ac+6bc+4c2-3a2–ab–2b^2
Thanks
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