Grade 128 grade maths
Simplify.
(ab + bc)^2– 2ab²cSimplify.
(ab + bc)^2– 2ab²c
Simplify.
(ab + bc)^2– 2ab²c
(ab + bc)^2– 2ab²c
Simplify.
(ab + bc)^2– 2ab²c
(ab + bc)^2– 2ab²c
1 Answer
Harshit Singh
Dear Student
(ab + bc)^2– 2ab²c
= a^2b^2+ 2ab^2c + b^2c^2- 2ab^2c
= a^2b^2+ b^2c^2
Thanks
(ab + bc)^2– 2ab²c
= a^2b^2+ 2ab^2c + b^2c^2- 2ab^2c
= a^2b^2+ b^2c^2
Thanks
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