Grade 128 grade maths
Simplify.
(a + b) (c – d) + (a – b) (c + d) + 2 (ac + bd)
Simplify.
(a + b) (c – d) + (a – b) (c + d) + 2 (ac + bd)
(a + b) (c – d) + (a – b) (c + d) + 2 (ac + bd)
1 Answer
Harshit Singh
Dear Student
(a + b) (c – d) + (a – b) (c + d) + 2 (ac + bd)
= (a + b) (c–d) + (a–b) (c + d) + 2 (ac + bd)
=(ac - ad + bc - bd) + (ac + ad - bc - bd) + (2ac + 2bd)
= ac - ad + bc - bd + ac + ad - bc - bd + 2ac + 2bd= 4ac
Thanks
(a + b) (c – d) + (a – b) (c + d) + 2 (ac + bd)
= (a + b) (c–d) + (a–b) (c + d) + 2 (ac + bd)
=(ac - ad + bc - bd) + (ac + ad - bc - bd) + (2ac + 2bd)
= ac - ad + bc - bd + ac + ad - bc - bd + 2ac + 2bd= 4ac
Thanks
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