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Dear Student7x^2 (3x – 9) + 3Solve for 7x^2 (3x – 9)= (7x^2× 3x) – (7x^2× 9) (using distributive law: a(b – c) = ab – ac)= 21x^3– 63x^2So, 7x^2 (3x – 9) + 3= 21x^3– 63x^2+ 3Now, for x = 4,21x^3– 63x^2+ 3= 21 × 43– 63 × 42+ 3= 1344 – 1008 + 3= 336 + 3 = 339Now, for x = 6,21x^3– 63x^2= 21 × 63– 63 × 62+ 3= 2268 + 3= 2271Thanks
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