Pls correct me Find max value of sin^113@.cos^113

Question

Pls correct meFind max value of sin^113@.cos^113@=> (1/2 )^113(2sin@cos@)^113=>(1/2)^113 (sin2@)^113Here I know that the max value of sin@=sin^2@=1But I am getting the angle as 2@. How to go with this?Thank you.

Arnav Prasad · Accepted Answer

Cos113@.Sin113@ = (Cos@.Sin@)113(Cos@.Sin@)113 = ((Sin2@)/2)113 NOTE :Maximum value of Sin2@ is same as that of Sin@.That is, 1.Proof? Let 2@ be ANY other angle. (Say X)Maximum of Sin(Any thing inside the function) = 1. (Sin2@)/2 = ½ = 2-1Therefore,((Sin2@)/2)113 maximum value is equal to (2-1)113. The final answer is 2-113.

8 grade maths> Pls correct me Find max value of sin^113@...

Pls correct me
Find max value of sin^113@.cos^113@
=> (1/2 )^113(2sin@cos@)^113
=>(1/2)^113 (sin2@)^113
Here I know that the max value of sin@=sin^2@=1
But I am getting the angle as 2@. How to go with this?
Thank you.

Seema , 10 Years ago

Arnav Prasad

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8 grade maths> Pls correct me Find max value of sin^113@...

Pls correct meFind max value of sin^113@.cos^113@=> (1/2 )^113(2sin@cos@)^113=>(1/2)^113 (sin2@)^113Here I know that the max value of sin@=sin^2@=1But I am getting the angle as 2@. How to go with this?Thank you.

Seema , 10 Years ago

Arnav Prasad

LIVE ONLINE CLASSES

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Pls correct me
Find max value of sin^113@.cos^113@
=> (1/2 )^113(2sin@cos@)^113
=>(1/2)^113 (sin2@)^113
Here I know that the max value of sin@=sin^2@=1
But I am getting the angle as 2@. How to go with this?
Thank you.