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In the given figure, the area of the parallelogram ABCD is

In the given figure, the area of the parallelogram ABCD is

Grade:8

2 Answers

Harshit Singh
askIITians Faculty 5875 Points
3 months ago
Dear student

By pythagoras theorem in right angled triangle AEC
h = 5 cm
Now , Area of parallelogram is given by multiplication of base and height

area = 10 x 5 = 50 cm2

Thanks
Gladan Delwin Dsouza
32 Points
3 months ago
It’s pretty simple
First, we find the length of CE :
Since Triangle AEC is a Right-angled triangle we use Pythagoras theorem 
12²+ CE² = 13²
CE²=25 Therefore CE = 5cm
 
Now we find length BE:
AE-DC = BE (as they are opposite sides of the parallelogram)
12-10 = 2 Therefore BE = 2cm
 
Hence we use Pythagoras theorem again in triangle BEC 
to find Hypotunuse side BC:
5²+2² = BC²
BC² = 29
BC = 5.3851cm
 
Hence area of the given figure:(Height × Base)
AB × BC 
10cm × 5.385cm = 53.851cm²

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