Grade 108 grade maths
In the given figure, the area of the parallelogram ABCD is
2 Answers
Harshit Singh
Dear student
By pythagoras theorem in right angled triangle AEC
h = 5 cm
Now , Area of parallelogram is given by multiplication of base and height
area = 10 x 5 = 50 cm2
Thanks
By pythagoras theorem in right angled triangle AEC
h = 5 cm
Now , Area of parallelogram is given by multiplication of base and height
area = 10 x 5 = 50 cm2
Thanks
Gladan Delwin Dsouza
It’s pretty simple
First, we find the length of CE :
Since Triangle AEC is a Right-angled triangle we use Pythagoras theorem
12²+ CE² = 13²
CE²=25 Therefore CE = 5cm
Now we find length BE:
AE-DC = BE (as they are opposite sides of the parallelogram)
12-10 = 2 Therefore BE = 2cm
Hence we use Pythagoras theorem again in triangle BEC
to find Hypotunuse side BC:
5²+2² = BC²
BC² = 29
BC = 5.3851cm
Hence area of the given figure:(Height × Base)
AB × BC
10cm × 5.385cm = 53.851cm²
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