In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5,06,000.

Question

Harshit Singh · Answer

Dear Student

The initial count of bacteria is given as 5,06,000.
Bacteria at the end of 2 hours=506000(1 +2.5/100 )^2
= 506000(1 +1/40 )^2
= 506000(1 + 41/40 )^2
= 531616.25
∴ The count of bacteria at the end of 2 hours will be 5,31,616 (approx.)

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In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5,06,000.

In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5,06,000.

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In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5,06,000.

In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5,06,000.

1 Answers

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