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Dear student,(a+1)(b+1)(c+1) = a+d+c+ab+bc+ca+abc+1So we can rewrite this equationa+b+c+ab+bc+ca+abc=1000as(a+1)(b+1)(c+1) - 1 = 1000so(a+1)(b+1)(c+1) = 1001which can be re written as(a+1)(b+1)(c+1) = 7*11*13if you look at this eqn closesly, these 7, 11 and 13 are prime numbers and can be rewritten as (6+1)*(10+1)*(12+1)So you can find that a+b+c = 28.
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