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If a,b,c are positive real numbers such that a+b-c/c =a-b+c/b =-a+b+c/a find the value of (a+b)(b+c)(c+a)/ABC

Syed shoukat , 6 Years ago
Grade 8
anser 3 Answers
Arun
Assuming that (a+b+c) is not equal to zero.
Given that,
a+b-c/c=a-b+c/b=-a+b+c/a= **sum of numerators/sum of denominators=1**(A property of ratios)
Therefore,
a+b=2c
a+c=2b
b+c=2a
Therefore,
(a+b)(b+c)(c+a)/abc=2c.2a.2b/abc=8
 
Last Activity: 6 Years ago
Vikas TU
Dear student 
Please follw the link below 
Good Luck 
Last Activity: 6 Years ago
Yashraj
we have solved in one place also so go to 
 
Last Activity: 5 Years ago
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