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Grade: 8
        
If a,b,c are positive real numbers such that a+b-c/c =a-b+c/b =-a+b+c/a find the value of (a+b)(b+c)(c+a)/ABC
 
4 months ago

Answers : (3)

Arun
24495 Points
							
Assuming that (a+b+c) is not equal to zero.
Given that,
a+b-c/c=a-b+c/b=-a+b+c/a= **sum of numerators/sum of denominators=1**(A property of ratios)
Therefore,
a+b=2c
a+c=2b
b+c=2a
Therefore,
(a+b)(b+c)(c+a)/abc=2c.2a.2b/abc=8
 
4 months ago
Vikas TU
11140 Points
4 months ago
Yashraj
337 Points
one month ago
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