Harshit Singh
Last Activity: 3 Years ago
Dear Student
Let the number of₹5 coins be x.
Then,
number ₹2 coins = 3x
and,number of ₹1 coins = (160- 4x) Now,Valueof₹5coins=x×5=5x Valueof₹2coins=3x×2=6x
Value of ₹1 coins = (160- 4x) × 1 = (160 - 4x)
According to the question, 5x+6x+(160-4x)=300⇒11x+160-4x=300
⇒7x=140
⇒x=140/7
⇒x=20
Numberof₹5coins=x=20
Numberof₹2coins=3x=60
Numberof₹1coins=(160-4x)=160-80=80
Thanks