For each of the following numbers, find the smallest whole number by which it should be multiplied so as to get a perfect square number. Also find the square root of the square number so obtained. 2028
Harshit Singh , 3 Years ago
Grade 12th pass
1 Answers
Harshit Singh
Last Activity: 3 Years ago
Dear Student 2028 = 2×2×3×13×13 = (2×2)×(13×13)×3 Here, 3 cannot be paired. ∴ We will multiply 2028 by 3 to get perfect square. New number = 2028×3 = 6084
6084 = 2×2×3×3×13×13
⇒ 6084 = (2×2)×(3×3)×(13×13)
⇒ 6084 =22×32×132
⇒ 6084 = (2×3×13)2
⇒ √6084 = 2×3×13 = 78 Thanks
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