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Find the smallest number by which 128 must be divided to obtain a perfect cube.

Pawan Prajapati , 4 Years ago
Grade 12
anser 1 Answers
Harshit Singh

Last Activity: 4 Years ago

Dear Student

The prime factorisation of 128 gives:

128 = 2×2×2×2×2×2×2

Now, if we group the factors in triplets of equal factors,

128 = (2×2×2)×(2×2×2)×2

Here, 2 cannot be grouped into triples of equal factors.

Therefore, we will divide 128 by 2 to get a perfect cube

Thanks

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