Flag 8 grade maths> Factorise x4 - 5x2 + 4 &l...
question mark

Factorise x4 - 5x2 + 4 < 0

Aniket Singh , 7 Months ago
Grade
anser 1 Answers
Askiitians Tutor Team

To factor the expression \(x^4 - 5x^2 + 4 < 0\), we can start by making a substitution. Let \(y = x^2\). This transforms the inequality into:

Rewriting the Inequality

The expression becomes:

y^2 - 5y + 4 < 0

Factoring the Quadratic

Next, we need to factor the quadratic equation:

y^2 - 5y + 4 = (y - 1)(y - 4)

Setting Up the Inequality

Now, we rewrite the inequality:

(y - 1)(y - 4) < 0

Finding the Critical Points

The critical points occur when each factor equals zero:

  • y - 1 = 0 → y = 1
  • y - 4 = 0 → y = 4

Analyzing the Intervals

We will test the intervals determined by these critical points: (-∞, 1), (1, 4), and (4, ∞).

  • For y < 1 (e.g., y = 0): (0 - 1)(0 - 4) = 4 > 0
  • For 1 < y < 4 (e.g., y = 2): (2 - 1)(2 - 4) = -2 < 0
  • For y > 4 (e.g., y = 5): (5 - 1)(5 - 4) = 4 > 0

Conclusion of the Analysis

The inequality (y - 1)(y - 4) < 0 holds true for the interval:

1 < y < 4

Returning to x

Substituting back \(y = x^2\), we have:

1 < x^2 < 4

Final Result

This means:

  • -2 < x < -1
  • 1 < x < 2

Thus, the solution to the inequality \(x^4 - 5x^2 + 4 < 0\) is:

x ∈ (-2, -1) ∪ (1, 2)

ApprovedApproved
Last Activity: 7 Months ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments