To factor the expression \(x^4 - 5x^2 + 4 < 0\), we can start by making a substitution. Let \(y = x^2\). This transforms the inequality into:
Rewriting the Inequality
The expression becomes:
y^2 - 5y + 4 < 0
Factoring the Quadratic
Next, we need to factor the quadratic equation:
y^2 - 5y + 4 = (y - 1)(y - 4)
Setting Up the Inequality
Now, we rewrite the inequality:
(y - 1)(y - 4) < 0
Finding the Critical Points
The critical points occur when each factor equals zero:
- y - 1 = 0 → y = 1
- y - 4 = 0 → y = 4
Analyzing the Intervals
We will test the intervals determined by these critical points: (-∞, 1), (1, 4), and (4, ∞).
- For y < 1 (e.g., y = 0): (0 - 1)(0 - 4) = 4 > 0
- For 1 < y < 4 (e.g., y = 2): (2 - 1)(2 - 4) = -2 < 0
- For y > 4 (e.g., y = 5): (5 - 1)(5 - 4) = 4 > 0
Conclusion of the Analysis
The inequality (y - 1)(y - 4) < 0 holds true for the interval:
1 < y < 4
Returning to x
Substituting back \(y = x^2\), we have:
1 < x^2 < 4
Final Result
This means:
Thus, the solution to the inequality \(x^4 - 5x^2 + 4 < 0\) is:
x ∈ (-2, -1) ∪ (1, 2)