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Factorise the expressions and divide them as directed. 4yz(z^2 +6z–16)÷2y(z+8)

 Factorise the expressions and divide them as directed.
 4yz(z^2 +6z–16)÷2y(z+8)

Grade:12

1 Answers

Harshit Singh
askIITians Faculty 5963 Points
3 years ago
Dear Student

Factorize z^2+6z–16,
z^2+6z–16 = z^2-2z+8z–16
= (z–2)(z+8)
Now, 4yz(z^2+6z–16) ÷ 2y(z+8)
= 4yz(z–2)(z+8)/2y(z+8)
= 2z(z-2)
​
Thanks

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