Grade 128 grade maths
Factorise. 25a^2 –4b^2 +28bc–49c^2 ??????????????????
Factorise.
25a^2 –4b^2 +28bc–49c^2 ??????????????????
1 Answer
Harshit Singh
Dear Student
= 25a^2–(4b^2-28bc+49c^2)
= (5a)^2-{(2b)^2-2(2b)(7c)+(7c)^2}
= (5a)^2-(2b-7c)^2
Using Identity: x^2-y^2= (x+y)(x-y) ,
we have = (5a+2b-7c)(5a-2b-7c)
Thanks
= 25a^2–(4b^2-28bc+49c^2)
= (5a)^2-{(2b)^2-2(2b)(7c)+(7c)^2}
= (5a)^2-(2b-7c)^2
Using Identity: x^2-y^2= (x+y)(x-y) ,
we have = (5a+2b-7c)(5a-2b-7c)
Thanks
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