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Each edge of a cube is increased by 50o/o. The percent of increase in the surface area of the cube is: (A ) 50 (B) 125 {C) 150 00)300

Each edge of a cube is increased by 50o/o. The percent of


increase in the surface area of the cube is:


(A ) 50 (B) 125 {C) 150 00)300

Grade:Upto college level

5 Answers

Amit Nardiya
askIITians Faculty 24 Points
7 years ago
Ans- B (125%)

Thanks & Regards,
Amit Nardiya,
askIITians faculty.
202-2252_8th.jpg
SREE NIGAMADITYA NIMMAGADDA
35 Points
7 years ago
let edge of cube be "a" surface area of cube =6a^2 after the increase, the new edge= a+a*50/100 which is equal to =3a/2 the new suface area =6*(3a/2)^2 =27a^2/2 increased percentage = 27a^2/2-6a^2/6a^2*100 which is equal to 125 %
Ansh Agrawal
55 Points
7 years ago
125 %
Prajwal Kavad
603 Points
6 years ago
125% increase in surface area, use differentiation to solve
Adarsh
733 Points
6 years ago
When each edge is increased by 50% its surface area will be increased by 125% 

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