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Each edge of a cube is increased by 50o/o. The percent of

increase in the surface area of the cube is:

(A ) 50 (B) 125 {C) 150 00)300

modassir anwer , 11 Years ago
Grade Upto college level
anser 5 Answers
Amit Nardiya

Last Activity: 11 Years ago

Ans- B (125%)

Thanks & Regards,
Amit Nardiya,
askIITians faculty.
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SREE NIGAMADITYA NIMMAGADDA

Last Activity: 10 Years ago

let edge of cube be "a" surface area of cube =6a^2 after the increase, the new edge= a+a*50/100 which is equal to =3a/2 the new suface area =6*(3a/2)^2 =27a^2/2 increased percentage = 27a^2/2-6a^2/6a^2*100 which is equal to 125 %

Ansh Agrawal

Last Activity: 10 Years ago

125 %

Prajwal Kavad

Last Activity: 9 Years ago

125% increase in surface area, use differentiation to solve

Adarsh

Last Activity: 9 Years ago

When each edge is increased by 50% its surface area will be increased by 125% 

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