# construct a quadrilateral ABCD in which AB=5.6cm BC=4cm CD=5cm DA=2cm

2081 Points
4 years ago
hello yuvi, the ques you have asked is not correct as there are infinitely many such quads. in any ques of construction, the reqd fig to be drawn should be unique.
in fact, u cn draw a line AB= 5.6 and BC= 4 for a random angle ABC. then, taking A as centre and radius= 2, draw an arc. now, taking C as centre and radius= 5, draw another arc, and let it intersect the previous arc at D. you ll have one of the infinitely many possible quadrilaterals ABCD
KINDLY APPROVE :)
Vikas TU
14149 Points
4 years ago
Dear student
∠A + ∠B + ∠C + ∠D = 360°
so 50° + 105° + ∠C + 80° = 360°
∠C = 125°
Now we will construct the quadrilateral  ABCD
- First we will draw a line AB = 5.6 cm
- Now we will draw ∠BAX = 50° and ∠ABY = 105° (you can use protector for this)
- The radius we will take is 4cm and the center will be B for that you will draw and arc which will intersect the line BY at "C"
- Now we will draw an angle of 125° at "C" and the angle ray line AX at "D"
Good Luck