Ashwin’s age is four times his son’s present age. 4 years ago, Ashwin was 6 times as old as his son. Find the present’s age of Ashwin’s son.

To solve the problem, let's define the variables for Ashwin's age and his son's age. Let S represent the son's current age. Therefore, Ashwin's current age can be expressed as 4S since he is four times his son's age.

Setting Up the Equation

According to the information given, four years ago, Ashwin was six times as old as his son. We can express their ages four years ago as follows:

• Ashwin's age four years ago: 4S - 4
• Son's age four years ago: S - 4

Creating the Equation

From the problem statement, we can set up the equation:

4S - 4 = 6(S - 4)

Solving the Equation

Now, let's simplify and solve the equation:

• Expand the right side: 4S - 4 = 6S - 24
• Rearranging gives: 4S - 6S = -24 + 4
• This simplifies to: -2S = -20
• Dividing by -2 results in: S = 10

Conclusion

Ashwin's son is currently 10 years old.