Grade 128 grade maths
Add the following.2p^2q^2 – 3pq + 4, 5 + 7pq – 3p^2q^2
Add the following.
2p^2q^2 – 3pq + 4, 5 + 7pq – 3p^2q^2
1 Answer
Harshit Singh
Dear Student
2p^2q^2–3pq + 4, 5 + 7pq–3p^2q^2
= (2p^2q^2- 3pq + 4) + (5 + 7pq - 3p^2q^2)
= 2p^2q^2- 3p^2q^2- 3pq + 7pq + 4 + 5
= - p^2q^2+ 4pq + 9
Thanks
2p^2q^2–3pq + 4, 5 + 7pq–3p^2q^2
= (2p^2q^2- 3pq + 4) + (5 + 7pq - 3p^2q^2)
= 2p^2q^2- 3p^2q^2- 3pq + 7pq + 4 + 5
= - p^2q^2+ 4pq + 9
Thanks
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