noogler
Last Activity: 9 Years ago
y=2xzlog(b)/(x+z)log(3)
let ax=3y=cz=k(cnstant)
a=k1/x,3=k1/y,c=k1/z
given ac=b2
k1/x . k1/z=b2
k1/x+1/z=b2
kx+z/xz=b2
k = b2xz/x+z
substitute k value in 3=k1/y
3=b2xz/(x+z)y
apply logarithm on both sides
log3=2xzlog(b) /(x+z)y log(ax)=xlog(a)
y=2xzlog(b)/(x+z)log(3)