A tin holds 16 1/2 liters of oil. How many such tins will be required to hold 313 1/2 liters of oil?

Let's break down the problem step by step:

We are given:

A tin holds 16 1/2 liters of oil.
We need to find how many tins are required to hold 313 1/2 liters of oil.
First, convert the mixed numbers into improper fractions.

For 16 1/2 liters, we have: 16 1/2 = (16 * 2 + 1)/2 = 33/2 liters.

For 313 1/2 liters, we have: 313 1/2 = (313 * 2 + 1)/2 = 627/2 liters.

Now, divide the total amount of oil (627/2 liters) by the amount of oil one tin holds (33/2 liters):

(627/2) ÷ (33/2)

To divide fractions, multiply the first fraction by the reciprocal of the second fraction: (627/2) * (2/33)

Simplify the 2's: 627/33

Now, divide 627 by 33: 627 ÷ 33 = 19

So, 19 tins will be required to hold 313 1/2 liters of oil.

The answer is 19 tins.