Grade 128 grade maths
(2a+3b)(a–b) = 2a^2 –3b^2 ?????????????????????????????
(2a+3b)(a–b) = 2a^2 –3b^2 ?????????????????????????????
1 Answer
Harshit Singh
Dear Student
LHS = (2a+3b)(a–b) = 2a(a–b)+3b(a–b)
= 2a^2–2ab+3ab–3b^2
= 2a^2+ab–3b^2
≠2a^2–3b^2 = RHS
The correct statement is (2a +3b)(a–b) = 2a^2+ab–3b^2
Thanks
LHS = (2a+3b)(a–b) = 2a(a–b)+3b(a–b)
= 2a^2–2ab+3ab–3b^2
= 2a^2+ab–3b^2
≠2a^2–3b^2 = RHS
The correct statement is (2a +3b)(a–b) = 2a^2+ab–3b^2
Thanks
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