Rishi Sharma
Last Activity: 4 Years ago
Dear Student,
Please find below the solution to your problem.
When one electron from neutral helium atom is removed, it becomes hydrogen like. The ionisation energy of hydrogen like atom is given by
Eion = Z^2Rhc
for helium, Z=2 Rhc=13.6eV
∴ Energy required to liberate second electron from helium
E2 = Eion = 22×13.6eV = −54eV
∴ Energy required to remove both the electrons from helium is
= E1+E2 = (24.6+54.4)eV = 79.0eV
Thanks and Regards