The sum of two numbers is 60 and their difference is 30.

The equation formed is

Dear Student

As per the condition given in the question, difference of the two numbers is 30.
So, 60–2x = 30
Transpose, -2x to RHS then it becomes 2x and 30 to LHS it becomes -30,

60–30 = 2x
30 = 2x
2x–30 = 0

Thanks