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7 grade maths

The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. Find the total price of 12 chairs and 3 tables.A) Rs 3500B) Rs 3750C) Rs 3840D) Rs 3900

Profile image of Aniket Singh
1 Year agoGrade
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1 Answer

Profile image of Askiitians Tutor Team
1 Year ago

Let's denote:

The price of one chair as C
The price of one table as T
We are given two pieces of information:

The price of 10 chairs is equal to the price of 4 tables. This gives the equation: 10C = 4T

The total price of 15 chairs and 2 tables together is Rs. 4000. This gives the equation: 15C + 2T = 4000

Step 1: Solve the first equation for T
From the first equation, 10C = 4T, we can solve for T: T = 10C / 4 T = 5C / 2

Step 2: Substitute the value of T into the second equation
Now, substitute T = 5C / 2 into the second equation (15C + 2T = 4000): 15C + 2(5C / 2) = 4000 15C + 5C = 4000 20C = 4000

Step 3: Solve for C
Now, divide both sides of the equation by 20: C = 4000 / 20 C = 200

Step 4: Find the value of T
Substitute C = 200 into T = 5C / 2: T = 5(200) / 2 T = 1000 / 2 T = 500

Step 5: Calculate the total price of 12 chairs and 3 tables
Now that we know the price of one chair (C = 200) and the price of one table (T = 500), we can calculate the total price of 12 chairs and 3 tables: Total price = 12C + 3T Total price = 12(200) + 3(500) Total price = 2400 + 1500 Total price = 3900

Thus, the total price of 12 chairs and 3 tables is Rs. 3900.

Answer: D) Rs. 3900