7 grade maths> The ascending arrangement of (2/3), (6/7)...
1 AnswersLast Activity: 4 Years ago
Dear Student
Option (b) is correct here
LCM of 21, 3, 7 = 21
Now, let us change each of the given fraction into an equivalent fraction having 21 as the denominator.
[(13/21) × (1/1)] = (13/21) [(2/3) × (7/7)] = (14/21) [(6/7) × (3/3)] = (18/21)
Clearly,
(13/21) < (14/21) < (18/21)
Hence,
(13/21) < (2/3) < (6/7)
Hence, the given fractions in ascending order are (13/21), (2/3), (6/7)
Thanks
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