Last Activity: 4 Years ago
Dear Student Factors of 32 = 2 × 2 × 2 × 2 × 2 = 2^5Factors of 4 = 2 × 2 = 2^2 Then,= (2^3× 3^4× 2^2)/ (3 × 2^5)= (2^3 + 2× 3^4) / (3 × 2^5) ... [∵(a^m x a^n ) = a^m+n= (2^5× 3^4) / (3 × 2^5)=2^5-5 x 3^4-1 ... [∵a^m÷a^n = a^m-n]=2^0× 3^3= 1 × 3^3= 3^3Thanks
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Last Activity: 3 Years ago