Harshit Singh
Last Activity: 3 Years ago
Dear Student
Let us consider Left Hand Side (LHS) = 10 × 10^11
10^1 + 11= 10^12 ... [∵a^m × a^n = a^m + n]
Now, consider Right Hand Side (RHS) = 100^11
= (10 × 10)^11
= (10^1 + 1)^11
= (10^2)^11
= (10)^2x11 ...[∵(a^m )^n = a^mn ]
=(10)^22
Thanks