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If a=5 and b=403 , then find the value of {1a2+1b2+2a+b(1a+1b)}⎡⎣{(a+b)2ab}−1⎤⎦ .

If a=5
and b=403
, then find the value of {1a2+1b2+2a+b(1a+1b)}⎡⎣{(a+b)2ab}−1⎤⎦
.

Grade:12th pass

1 Answers

Pawan Prajapati
askIITians Faculty 60796 Points
2 months ago
Our expert is working on this Class VII Maths answer. We will update the answer very soon.

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