If a=5
and b=403
, then find the value of {1a2+1b2+2a+b(1a+1b)}⎡⎣{(a+b)2ab}−1⎤⎦
.

Question

If a=5 and b=403 , then find the value of {1a2+1b2+2a+b(1a+1b)}⎡⎣{(a+b)2ab}−1⎤⎦ .

Pawan Prajapati · Answer

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If a=5 and b=403 , then find the value of {1a2+1b2+2a+b(1a+1b)}⎡⎣{(a+b)2ab}−1⎤⎦ .

If a=5
and b=403
, then find the value of {1a2+1b2+2a+b(1a+1b)}⎡⎣{(a+b)2ab}−1⎤⎦
.

1 Answers

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If a=5 and b=403 , then find the value of {1a2+1b2+2a+b(1a+1b)}⎡⎣{(a+b)2ab}−1⎤⎦ .

If a=5 and b=403 , then find the value of {1a2+1b2+2a+b(1a+1b)}⎡⎣{(a+b)2ab}−1⎤⎦ .

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If a=5
and b=403
, then find the value of {1a2+1b2+2a+b(1a+1b)}⎡⎣{(a+b)2ab}−1⎤⎦
.