Dear Student
From the question it is given that, Diameter of the circular table-top = 1.6 m
We know that, radius (r) = d/2
= 1.6/2
= 0.8 m
Then,
Area of the circular table-top =πr^2
= 3.14 × 0.8^2
= 3.14 × 0.8 ×0.8
= 2.0096 m^2
Cost for polishing 1 m^2area =₹15 From the question it is given that, Diameter of the circular table-top = 1.6 m We know that, radius (r) = d/2
= 1.6/2 = 0.8 m
Then,
Area of the circular table-top =πr^2
= 3.14 × 0.82
= 3.14 × 0.8 ×0.8 = 2.0096 m^2
Cost for polishing 1 m^2area =₹15 [given]
Cost for polishing 2.0096 m^2area =₹15 × 2.0096
=₹30.144
Hence, the Cost for polishing 2.0096 m2area is₹30.144.
Thanks
