Find 3 consecutive positive even integers whose sum is 90

Let's call the three consecutive positive even integers x, x + 2, and x + 4, where x is the first even integer. Now we can set up an equation based on the given information:

x + (x + 2) + (x + 4) = 90

Now, let's solve for x:

3x + 6 = 90

Subtract 6 from both sides of the equation:

3x = 90 - 6
3x = 84

Now, divide both sides by 3 to find the value of x:

x = 84 / 3
x = 28

So, the first even integer (x) is 28. Now, we can find the other two consecutive positive even integers:

The second even integer: x + 2 = 28 + 2 = 30
The third even integer: x + 4 = 28 + 4 = 32

So, the three consecutive positive even integers whose sum is 90 are 28, 30, and 32.