badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 7

                        

A biquadratic polynomial f(x) has zeroes -2,3,5 and 7. if f(0)=1 then the remainder when f(x) is divided by (x-1)

one year ago

Answers : (2)

Arun
25141 Points
							
Dear student
 
f(x) = a (x+2) (x-3)(x-5)(x-7)
Now f(0) = 1 = – 210 a
a = -1 /210
 
hence f(x) = – (x+2) (x-3)(x-5)(x-7)/210
 
hence by remainder theorem when divisible by (x-1)
remainder = 315/210 = 1.5
one year ago
Yashraj
356 Points
							
since  zeroes are -2,3,5 and 7.
f(x) = a (x+2) (x-3)(x-5)(x-7)
f of o is 1 
so a =-1/210
to find remainder put x=-1
in equation
6 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 728 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details