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A biquadratic polynomial f(x) has zeroes -2,3,5 and 7. if f(0)=1 then the remainder when f(x) is divided by (x-1)

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one year ago

```							Dear student f(x) = a (x+2) (x-3)(x-5)(x-7)Now f(0) = 1 = – 210 aa = -1 /210 hence f(x) = – (x+2) (x-3)(x-5)(x-7)/210 hence by remainder theorem when divisible by (x-1)remainder = 315/210 = 1.5
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one year ago
```							since  zeroes are -2,3,5 and 7.f(x) = a (x+2) (x-3)(x-5)(x-7)f of o is 1 so a =-1/210to find remainder put x=-1in equation
```
6 months ago
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