Last Activity: 3 Years ago
Dear Student(b) -52 and 52(-52) + (+52) = 0[(-a) + (+a) = 0](d) -50, -200 and 300(-50) + (-200) + (+300)= (-50) + (-200) + (+200) + (+100)= (-50) + 0 + (+100) [(-a) + (+a)= 0]= (-50) + (+100)= (-50) + (+50) + (+50)= 0 + (+50) [(-a) + (+a) = 0]=50Thanks
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Last Activity: 2 Year ago(s)