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Grade 12th pass6 grade maths

Find the sum of: (a) 137 and -354 (b) -52 and 52 . (d) -312, 39 and 192 (d) -50, -200 and 300

Profile image of Harshit Singh
5 Years agoGrade 12th pass
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1 Answer

Profile image of Pawan Prajapati
5 Years ago
Solution: (a) 137 and -354 (137) + ( -354) = (137) + (-137) + (-217) [∵ (137) + (-137) = 0] = 0 + (-217) = (-217) (b) -52 and 52 (-52) + (+52) = 0 [ ∵ (-a) + (+ a) = 0] (c) -312, 39 and 192 (-312) + (+ 39) + (+192) = (-231) + (- 81) + (+39) + (+192) = (-231) + (-81) + (+ 231) = (-231) + (+ 231) + (-81) [∵ (-a) + (a) = 0] = 0 + (- 81) = – 81 (d) – 50, -200 and 300 (-50) + (-200) + (+ 300) = (-50) + (-200) + (+200) + (+100) = (-50) + 0 + (+100)[∵ (-a) + (+ a) = 0] = (-50) + (+100) = (-50) + (+50) + (+ 50) = 0 + (+ 50) = 50 [ ∵ (-a) + (+ a) = 0]