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Find all n ? N, such that the equation (x-8/n-10)=(n/x) has no solution x.
(x-8)/(n-10)=n/x=>x(x-8)=n(n-10)=>x^2-8x-n(n-10)=0For Eq has no solution in x, B^2-4AC<0=>64+4(1)(n)(n-10)<0=>16+n(n-10)<0=>n^2-10n+16<0=>(n-8)(n-2)<0=> 2 <n<8So n=3,4,5,6,7Thanks & RegardsRinkoo GuptaAskIITians Faculty
(x-8)/(n-10)=n/x=>x(x-8)=n(n-10)=>x^2-8x-n(n-10)=0For Eq has no solution in x, B^2-4AC=>64+4(1)(n)(n-10)=>16+n(n-10)=>n^2-10n+16=>(n-8)(n-2)=> 2 So n=3,4,5,6,7
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